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0.04z^2+0.04z-7=0
a = 0.04; b = 0.04; c = -7;
Δ = b2-4ac
Δ = 0.042-4·0.04·(-7)
Δ = 1.1216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.04)-\sqrt{1.1216}}{2*0.04}=\frac{-0.04-\sqrt{1.1216}}{0.08} $$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.04)+\sqrt{1.1216}}{2*0.04}=\frac{-0.04+\sqrt{1.1216}}{0.08} $
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